(2x+1)*(3x^2+2x+1)=0

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Solution for (2x+1)*(3x^2+2x+1)=0 equation: 


Simplifying
(2x + 1)(3x2 + 2x + 1) = 0

Reorder the terms:
(1 + 2x)(3x2 + 2x + 1) = 0

Reorder the terms:
(1 + 2x)(1 + 2x + 3x2) = 0

Multiply (1 + 2x) * (1 + 2x + 3x2)
(1(1 + 2x + 3x2) + 2x * (1 + 2x + 3x2)) = 0
((1 * 1 + 2x * 1 + 3x2 * 1) + 2x * (1 + 2x + 3x2)) = 0
((1 + 2x + 3x2) + 2x * (1 + 2x + 3x2)) = 0
(1 + 2x + 3x2 + (1 * 2x + 2x * 2x + 3x2 * 2x)) = 0
(1 + 2x + 3x2 + (2x + 4x2 + 6x3)) = 0

Reorder the terms:
(1 + 2x + 2x + 3x2 + 4x2 + 6x3) = 0

Combine like terms: 2x + 2x = 4x
(1 + 4x + 3x2 + 4x2 + 6x3) = 0

Combine like terms: 3x2 + 4x2 = 7x2
(1 + 4x + 7x2 + 6x3) = 0

Solving
1 + 4x + 7x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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